当前结点在二叉树表示中的深度等于父结点深度加上当前节点左兄弟的个数再加1
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#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
#define N 40005
int main(int argc, char *argv[])
{
char s[N];
int tree_depth;
int father[N];
int bi_depth[N];
int left_child[N];
int max_tree_depth, max_bi_depth;
int num = 0;
while (1) {
++num;
scanf("%s", s);
int len = strlen(s);
if (s[0] == '#')
break;
tree_depth = 0;
max_tree_depth = 0;
max_bi_depth = 0;
memset(father, 0, N * sizeof(int));
memset(bi_depth, 0, N * sizeof(int));
memset(left_child, 0, N * sizeof(int));
for (int i = 1; i <= len; ++i) {
if (s[i-1] == 'd') {
++tree_depth;
if (max_tree_depth < tree_depth)
max_tree_depth = tree_depth;
father[i] = i - 1;
bi_depth[i] = bi_depth[i-1] + left_child[i-1] + 1;
++left_child[i-1];
if (max_bi_depth < bi_depth[i])
max_bi_depth = bi_depth[i];
}
else if (s[i-1] == 'u') {
--tree_depth;
bi_depth[i] = bi_depth[father[i-1]];
left_child[i] = left_child[father[i-1]];
father[i] = father[father[i-1]];
}
}
printf("Tree %d: %d => %d\n", num, max_tree_depth, max_bi_depth);
}
return 0;
}
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